Question

problem 2
draw two rectangles that have the same area, but are not congruent.

Explanation:

Step1: Recall rectangle - area formula

The area of a rectangle is \(A = l\times w\) (where \(l\) is the length and \(w\) is the width).

Step2: Choose dimensions

Let the first rectangle have length \(l_1 = 4\) and width \(w_1=3\), so its area \(A_1=4\times3 = 12\).
Let the second rectangle have length \(l_2 = 6\) and width \(w_2 = 2\), so its area \(A_2=6\times2=12\).
Since \(A_1 = A_2=12\), and the rectangles have different side - lengths, they are not congruent.
We can draw a rectangle with length 4 units and width 3 units and another rectangle with length 6 units and width 2 units.

Answer:

Draw a rectangle with length 4 units and width 3 units and a rectangle with length 6 units and width 2 units.