Question

problem 5: an elevator motor pulls up an elevator with a force of 6500 n. if the elevator is going at a constant velocity of 3 m/s. find the power generated by the motor.

Explanation:

Step1: Recall power - force - velocity formula

The formula for power $P$ when a force $F$ acts on an object moving with a velocity $v$ in the direction of the force is $P = Fv$.

Step2: Substitute given values

We are given that $F = 6500\ N$ and $v=3\ m/s$. Substituting these values into the formula $P = Fv$, we get $P=(6500\ N)\times(3\ m/s)$.

Step3: Calculate the power

$P = 19500\ W$.

Answer:

$19500\ W$