Question

problem 4: two kids are playing tug of war by pulling on a rope. kid one pulls with a force of 340 n to the right (positive). the other child, kid 2, pulls with a force of -290 n (to the left). kid 1 wins by pulling the rope (and everyone) a distance of 5 m. find the total work done on the rope.

Explanation:

Step1: Calculate net force

The net force $F_{net}$ is the sum of the two forces. $F_{net}=F_1 + F_2$, where $F_1 = 340\ N$ and $F_2=- 290\ N$. So $F_{net}=340+( - 290)=50\ N$.

Step2: Calculate work - done

The work - done formula is $W = F_{net}\times d$, where $d = 5\ m$ and $F_{net}=50\ N$. So $W=50\times5 = 250\ J$.

Answer:

$250\ J$