Question

put these values in order from least to greatest.
3π
32.3
√66
39/4
submit

Explanation:

Step1: Calculate each value

• For \(3\pi\): \(\pi\approx3.14\), so \(3\pi\approx3\times3.14 = 9.42\)
• For \(\sqrt{66}\): \(8^2 = 64\), \(9^2 = 81\), so \(\sqrt{66}\approx8.12\) (wait, no, 8^2=64, 8.1^2=65.61, 8.12^2≈65.93, 8.13^2≈66.09, so \(\sqrt{66}\approx8.12\)? Wait, no, that can't be. Wait, 8^2=64, 9^2=81, so \(\sqrt{66}\) is between 8 and 9. Wait, 8.1^2=65.61, 8.2^2=67.24, so \(\sqrt{66}\approx8.12\)? Wait, no, 8.12^2 = 65.9344, 8.13^2=66.0969, so \(\sqrt{66}\approx8.12\)? Wait, that's wrong. Wait, 39/4 is 9.75, 3π is ~9.42, 32.3 is 32.3, √66 is ~8.12. Wait, no, I must have miscalculated. Wait, 39 divided by 4 is 9.75. 3π is 3*3.1416≈9.4248. √66: 8^2=64, 9^2=81, so √66 is about 8.124. So let's list all values:

• \(3\pi\approx9.42\)
• \(32.3 = 32.3\)
• \(\sqrt{66}\approx8.12\)
• \(\frac{39}{4}=9.75\)

Step2: Order from least to greatest

Now, compare the values:

\(\sqrt{66}\approx8.12\) < \(3\pi\approx9.42\) < \(\frac{39}{4}=9.75\) < \(32.3\)

Wait, that makes sense. Let's verify each:

• \(\sqrt{66}\approx8.12\) (smallest)
• \(3\pi\approx9.42\) (next)
• \(\frac{39}{4}=9.75\) (next)
• \(32.3\) (largest)

Answer:

\(\sqrt{66}\), \(3\pi\), \(\frac{39}{4}\), \(32.3\)