Question

pythagorean theorem and simplifying radicals practice
12 of 32
simplify.

1. \\(sqrt{20} \bullet sqrt{2}\\)

Explanation:

Step1: Combine the square roots

$\sqrt{20} \cdot \sqrt{2} = \sqrt{20 \times 2}$

Step2: Multiply the radicands

$\sqrt{20 \times 2} = \sqrt{40}$

Step3: Simplify the radical

$\sqrt{40} = \sqrt{4 \times 10} = \sqrt{4} \cdot \sqrt{10} = 2\sqrt{10}$

Answer:

$2\sqrt{10}$ (fill 2 in the first blank and 10 in the blank under the radical)