Question

q3 - mathematics gr 8 - section 1 | quiz 2
target due: tomorrow
a = (9, -8)
b = (8, -7)
c = (10, -4)
a. 3.00
b. 3.61
c. 4.12
d. 1.41

Explanation:

Step1: Identify target segment

We need to find the length of segment $A'B'$, with points $A'=(9, -8)$ and $B'=(8, -7)$.

Step2: Apply distance formula

Use the distance formula $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Substitute $x_1=9, y_1=-8, x_2=8, y_2=-7$:

$$\begin{align*} d&=\sqrt{(8-9)^2+(-7-(-8))^2}\\ &=\sqrt{(-1)^2+(1)^2}\\ &=\sqrt{1+1}\\ &=\sqrt{2} \end{align*}$$

Step3: Calculate decimal value

$\sqrt{2}\approx1.41$

Answer:

d. 1.41