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quadrilateral cdef is inscribed in circle a. if m∠c = 9x° and m∠e = 7x …

Question

quadrilateral cdef is inscribed in circle a. if m∠c = 9x° and m∠e = 7x + 4°, what is the measure of ∠e?
95°
99°
81°
85°

Explanation:

Step1: Recall property of cyclic quadrilateral

Opposite angles of a cyclic quadrilateral are supplementary, so \(m\angle C+m\angle E = 180^{\circ}\).

Step2: Substitute angle - measures

Substitute \(m\angle C = 9x^{\circ}\) and \(m\angle E=7x + 4^{\circ}\) into the equation: \(9x+(7x + 4)=180\).

Step3: Simplify the equation

Combine like - terms: \(9x+7x+4 = 180\), which gives \(16x+4 = 180\).

Step4: Solve for \(x\)

Subtract 4 from both sides: \(16x=180 - 4=176\). Then divide both sides by 16: \(x=\frac{176}{16}=11\).

Step5: Find \(m\angle E\)

Substitute \(x = 11\) into the expression for \(m\angle E\): \(m\angle E=7x + 4=7\times11+4=77 + 4=81^{\circ}\).

Answer:

\(81^{\circ}\)