Question

question 1-1 simplify the expression (7^-2)÷(7^-5). what is the result? 7^3 7^-7 7^-3 7^5

Explanation:

Step1: Apply exponent - division rule

$a^m\div a^n=a^{m - n}$, here $a = 7$, $m=-2$, $n = - 5$. So, $7^{-2}\div7^{-5}=7^{-2-(-5)}$.

Step2: Simplify the exponent

$-2-(-5)=-2 + 5=3$. So, $7^{-2-(-5)}=7^{3}$.

Answer:

$7^3$