Question

question 1 of 10
how many atoms does 32 g of sulfur contain?

a. $32 \times (6.02 \times 10^{23})$

b. $6.02 \times 10^{23}$

c. $\frac{6.02 \times 10^{23}}{16}$

d. $\frac{6.02 \times 10^{23}}{32}$

Explanation:

Step1: Recall molar mass and Avogadro's number

The molar mass of sulfur (S) is approximately 32 g/mol. Avogadro's number, \( N_A = 6.02\times10^{23} \) atoms/mol, represents the number of particles (atoms, molecules, etc.) in one mole of a substance.

Step2: Calculate moles of sulfur

Moles of sulfur \( n=\frac{\text{mass}}{\text{molar mass}}=\frac{32\,\text{g}}{32\,\text{g/mol}} = 1\,\text{mol} \).

Step3: Calculate number of atoms

Number of atoms \( = n\times N_A=1\,\text{mol}\times6.02\times10^{23}\,\text{atoms/mol}=6.02\times10^{23} \).

Answer:

B. \( 6.02 \times 10^{23} \)