Question

question 4 of 10 a projectile is fired with a velocity of 8 m/s at an angle of 65°. what is the vertical component of the velocity? a. 7.2 m/s b. 10.2 m/s c. 6.5 m/s d. 3.4 m/s

Explanation:

Step1: Recall velocity - component formula

The vertical - component of a velocity $v$ fired at an angle $\theta$ is given by $v_y = v\sin\theta$.

Step2: Substitute given values

We have $v = 8$ m/s and $\theta=65^{\circ}$. So $v_y=8\times\sin65^{\circ}$.
Since $\sin65^{\circ}\approx0.9063$, then $v_y = 8\times0.9063 = 7.2504\approx7.2$ m/s.

Answer:

A. 7.2 m/s