Question

question 8 of 10 solve the system of equations below. $x - 2y = 3$ $2x - 3y = 9$ a. $(-9, 3)$ b. $(-3, 9)$ c. $(9, 3)$ d. $(3, 9)$

Explanation:

Step1: Solve for x from first equation

From \( x - 2y = 3 \), we get \( x = 2y + 3 \).

Step2: Substitute x into second equation

Substitute \( x = 2y + 3 \) into \( 2x - 3y = 9 \):
\( 2(2y + 3) - 3y = 9 \)
\( 4y + 6 - 3y = 9 \)
\( y + 6 = 9 \)
\( y = 9 - 6 = 3 \)

Step3: Find x using y = 3

Substitute \( y = 3 \) into \( x = 2y + 3 \):
\( x = 2\times3 + 3 = 6 + 3 = 9 \)

Answer:

C. (9, 3)