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question 4 of 10 step 2 of 2
00:51:21
consider the following function on the given domain.
$a(x) = (x + 1)^2 + 3, x \geq -1$
step 2 of 2: find the domain of the inverse function, $a^{-1}(x)$. express your answer as an inequality.
answer 2 points
Step1: Find range of $A(x)$
For $x\geq -1$, let $t=x+1$, so $t\geq0$. Then $A(x)=t^2+3$. Since $t^2\geq0$, $t^2+3\geq3$.
Step2: Relate range to inverse domain
The domain of $A^{-1}(x)$ equals the range of $A(x)$.
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$x\geq 3$