Question

question 4 of 10 what two steps are necessary to put this equation into standard form? (x^{2}-3x + 16=6x - 4) a. add 4 to both sides and add 6x from both sides. b. subtract 4 both sides and add 6x from both sides. c. add 4 to both sides and subtract 6x from both sides. d. the equation is already in standard form.

Explanation:

Step1: Recall standard - form of quadratic

The standard form of a quadratic equation is $ax^{2}+bx + c=0$.

Step2: Rearrange given equation

For the equation $x^{2}-3x + 16=6x-4$, we first add 4 to both sides to get $x^{2}-3x+16 + 4=6x-4 + 4$, which simplifies to $x^{2}-3x + 20=6x$. Then we subtract $6x$ from both sides: $x^{2}-3x-6x + 20=6x-6x$, resulting in $x^{2}-9x + 20=0$.

Answer:

C. Add 4 to both sides and subtract 6x from both sides.