Question

question 1 of 10
you are tossing pizza dough to get it ready to bake. if you toss the dough upward with a speed of 3.1 m/s, how high does it go?
a. 1.2 m
b. 0.49 m
c. 0.77 m
d. 0.16 m

Explanation:

Step1: Identify the kinematic - equation

We use the equation $v^{2}=v_{0}^{2}-2gh$. At the maximum - height, the final velocity $v = 0$. The initial velocity $v_{0}=3.1\ m/s$ and the acceleration due to gravity $g = 9.8\ m/s^{2}$.

Step2: Solve for the height $h$

Rearranging the equation $v^{2}=v_{0}^{2}-2gh$ for $h$, we get $h=\frac{v_{0}^{2}-v^{2}}{2g}$. Substituting $v = 0$ and $v_{0}=3.1\ m/s$ and $g = 9.8\ m/s^{2}$ into the formula, we have $h=\frac{3.1^{2}-0^{2}}{2\times9.8}=\frac{9.61}{19.6}\approx0.49\ m$.

Answer:

B. 0.49 m