Question

question 5
a 12,000 kg pickup is moving across a parking lot at 9 m/s.
what is the pickups kinetic energy?
hint: $ke = \frac{1}{2}mv^{2}$
a 1,333.3 j
b 486,000 j
c 1,058,400 j

Explanation:

Step1: Identify values

$m = 12000$ kg, $v=9$ m/s

Step2: Apply kinetic - energy formula

$KE=\frac{1}{2}mv^{2}=\frac{1}{2}\times12000\times9^{2}$
$=\frac{1}{2}\times12000\times81$
$ = 6000\times81$
$=486000$ J

Answer:

B. 486,000 J