Question

question 12 (4 points) find the discriminant, then use it to determine the number of solutions and the type of solution for the given quadratic equation. upload your handwritten work displaying how you solved to receive credit. f(x) = 4x² + 4x + 1

Explanation:

Step1: Identify quadratic coefficients

For $f(x)=4x^2+4x+1$, $a=4$, $b=4$, $c=1$

Step2: Apply discriminant formula

Discriminant $D = b^2 - 4ac$
$D = 4^2 - 4(4)(1)$

Step3: Calculate discriminant value

$D = 16 - 16 = 0$

Step4: Interpret discriminant result

When $D=0$, there is 1 real repeated rational solution.

Answer:

Discriminant: $0$
Number of solutions: 1
Type of solutions: Real repeated rational solution