Question

question 13 of 20 (1 point) | question attempt: 1 of 3
part 2 of 3
26.0 g mgcl₂ in 7.66 l solution
m

Explanation:

Step1: Calculate molar mass of MgCl₂

Molar mass of MgCl₂ = $24.305\ \text{g/mol} + 2\times35.453\ \text{g/mol} = 95.211\ \text{g/mol}$

Step2: Find moles of MgCl₂

$\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{26.0\ \text{g}}{95.211\ \text{g/mol}} \approx 0.2731\ \text{mol}$

Step3: Calculate molarity (M)

$\text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution (L)}} = \frac{0.2731\ \text{mol}}{7.66\ \text{L}} \approx 0.0356\ \text{M}$

Answer:

$0.0356$ M