Question

question 14 (1 point) a solution contains 0.90 g of sodium chloride dissolved in 100 ml of solution. the molar concentration of the solution is 0.90 g/100 ml 526.6 m 0.15 mol/l 0.9% (v/v)

Explanation:

Step1: Calculate moles of NaCl

The molar mass of NaCl is $M = 58.44\ g/mol$. Given mass of NaCl is $m = 0.90\ g$. Using the formula $n=\frac{m}{M}$, we have $n=\frac{0.90\ g}{58.44\ g/mol}\approx0.0154\ mol$.

Step2: Convert volume to liters

The volume of the solution $V = 100\ mL=0.1\ L$.

Step3: Calculate molarity

Molarity $M=\frac{n}{V}$. Substituting $n = 0.0154\ mol$ and $V = 0.1\ L$, we get $M=\frac{0.0154\ mol}{0.1\ L}=0.154\ mol/L\approx0.15\ mol/L$.

Answer:

0.15 mol/L