Question

question 14 (1 point) which of the following molecules demonstrates a square pyramidal molecular structure? ccl4 xef4 ch4 xeo3

Explanation:

• For $CH_4$, the central - carbon atom has 4 bonding pairs and 0 lone pairs, resulting in a tetrahedral molecular geometry.
• For $CCl_4$, the central - carbon atom has 4 bonding pairs and 0 lone pairs, giving a tetrahedral molecular geometry.
• For $XeO_3$, the central xenon atom has 3 bonding pairs and 1 lone pair. According to VSEPR theory, it has a trigonal - pyramidal molecular geometry.
• For $XeF_4$, the central xenon atom has 4 bonding pairs and 2 lone pairs. By VSEPR theory, it has a square - planar electron - pair geometry and a square - pyramidal molecular geometry when considering the positions of the atoms only.

Answer:

XeF_4