Question

question 15 of 20 a softball pitcher throws a 0.17 kg ball toward a batter who is 20 m away. the ball is traveling at 22 m/s when it leaves the pitchers hand. what is the ball kinetic energy at this point? a. 82 j b. 41 j c. 4 j d. 2 j

Explanation:

Step1: Recall kinetic - energy formula

The formula for kinetic energy is $K = \frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the velocity.

Step2: Substitute given values

Given $m = 0.17\ kg$ and $v = 22\ m/s$. Substitute into the formula: $K=\frac{1}{2}\times0.17\times(22)^{2}$.

Step3: Calculate the result

First, calculate $(22)^{2}=484$. Then, $\frac{1}{2}\times0.17\times484 = 0.085\times484 = 41.14\ J\approx41\ J$.

Answer:

B. 41 J