Question

question 15 of 20
which conic section does the equation below describe?
\\(\frac{(x - 3)^2}{40}+\frac{(y + 5)^2}{4}=1\\)
a. parabola
b. circle
c. ellipse
d. hyperbola

Explanation:

The general form of an ellipse is $\frac{(x - h)^2}{a^2}+\frac{(y - k)^2}{b^2}=1$ where $(h,k)$ is the center, and $a$ and $b$ are non - zero. The given equation $\frac{(x - 3)^2}{40}+\frac{(y + 5)^2}{4}=1$ is in this form. A parabola has only one squared term, a circle has $a = b$, and a hyperbola has a difference of squares equal to 1.

Answer:

C. Ellipse