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Question
question 8 of 15, step 1 of 1
6/15
correct
t = 2π√(l/g). this is the formula for the period t of a pendulum of length l. solve this formula for g.
answer
Step1: Square both sides
$T^{2}=(2\pi\sqrt{\frac{l}{g}})^2 = 4\pi^{2}\frac{l}{g}$
Step2: Cross - multiply
$T^{2}g = 4\pi^{2}l$
Step3: Solve for g
$g=\frac{4\pi^{2}l}{T^{2}}$
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$g=\frac{4\pi^{2}l}{T^{2}}$