Question

question 16 of 20 identify the precipitate that forms and the spectator ions that remain in the solution following this reaction. answer bank bas(s) so₄²⁻(aq) k⁺(aq) kno₃(s) s²⁻(aq) bai₂(s) ba²⁺(aq) no₃⁻(aq) i⁻(aq) baso₄(s)

Explanation:

Step1: Recall solubility rules

Most sulfates are soluble except those of barium ($Ba^{2 + }$), lead ($Pb^{2+}$), calcium ($Ca^{2+}$) etc. Barium sulfate ($BaSO_{4}$) is insoluble and will form a precipitate. Spectator ions are those that do not participate in the actual chemical reaction and remain in solution.

Step2: Identify spectator ions

Potassium ($K^{+}$) and nitrate ($NO_{3}^{-}$) are common spectator - ions in many reactions as their salts are generally soluble.

Answer:

Precipitate: $BaSO_{4}(s)$
Spectator ions: $K^{+}(aq), NO_{3}^{-}(aq)$