Question

question 16, 2.8.43 part 1 of 6 give the center and radius of the circle described by the equation and graph the equation. use the graph to identify the relations domain and range. (x - 5)^2+(y - 1)^2 = 9 what is the center of the circle? the circle is centered at the point . (type an ordered pair.)

Explanation:

Step1: Recall circle - equation form

The standard form of a circle's equation is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius.

Step2: Identify center values

For the equation $(x - 5)^2+(y - 1)^2=9$, comparing with the standard form, we have $h = 5$ and $k = 1$.

Answer:

$(5,1)$