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Question
question 16
1 pts
what are the coordinates of the point 1/4 of the way from a(-6, -3) to b(10, 9) on the line segment ab?
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Step1: Find the difference in x - coordinates
The difference in x - coordinates $\Delta x=x_B - x_A$, where $x_A=-6$ and $x_B = 10$. So, $\Delta x=10-(-6)=16$.
Step2: Find the difference in y - coordinates
The difference in y - coordinates $\Delta y=y_B - y_A$, where $y_A=-3$ and $y_B = 9$. So, $\Delta y=9-(-3)=12$.
Step3: Calculate the x - coordinate of the point
The x - coordinate of the point that is $\frac{1}{4}$ of the way from A to B is $x=x_A+\frac{1}{4}\Delta x$. Substitute $x_A=-6$ and $\Delta x = 16$ into the formula: $x=-6+\frac{1}{4}\times16=-6 + 4=-2$.
Step4: Calculate the y - coordinate of the point
The y - coordinate of the point that is $\frac{1}{4}$ of the way from A to B is $y=y_A+\frac{1}{4}\Delta y$. Substitute $y_A=-3$ and $\Delta y = 12$ into the formula: $y=-3+\frac{1}{4}\times12=-3 + 3=0$.
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