Question

question 19 of 30
what is the product of the unbalanced equation below?
al(s) + br₂(g) →
the periodic table
a. al(s) + br₂(g)
b. albr₃(s)
c. albr(s)
d. al₂br₃(s)

Explanation:

Step1: Determine the oxidation states

Aluminum (Al) has an oxidation state of +3 and bromine (Br) in $Br_2$ has an oxidation state of -1 in its compounds.

Step2: Combine elements to form product

To form a neutral - compound, we need 3 bromine atoms for every aluminum atom. So the product of the reaction between aluminum and bromine is aluminum bromide with the formula $AlBr_3$.

Answer:

B. $AlBr_3(s)$