Question

question 20 (5 points) what mass of carbon monoxide is produced when 1.50 mol of oxygen reacts completely in the following equation? 2c + o2 2co
a) 84.0 g
b) 42.0 g
c) 28.0 g
d) 21.0 g

Explanation:

Step1: Determine mole ratio

From the equation \(2C + O_2
ightarrow 2CO\), the mole ratio of \(O_2\) to \(CO\) is \(1:2\).

Step2: Calculate moles of CO

Moles of \(O_2 = 1.50\) mol. So moles of \(CO = 2\times1.50 = 3.00\) mol.

Step3: Calculate molar mass of CO

Molar mass of \(C = 12.01\) g/mol, \(O = 16.00\) g/mol. Molar mass of \(CO = 12.01 + 16.00 = 28.01\) g/mol.

Step4: Calculate mass of CO

Mass = moles × molar mass = \(3.00\) mol × \(28.01\) g/mol ≈ \(84.0\) g? Wait, no, wait. Wait, the equation is \(2C + O_2
ightarrow 2CO\), so 1 mol \(O_2\) produces 2 mol \(CO\). So 1.50 mol \(O_2\) produces \(2\times1.50 = 3.00\) mol \(CO\). Molar mass of \(CO\) is \(12 + 16 = 28\) g/mol. So mass is \(3.00\) mol × \(28\) g/mol = \(84.0\) g? But the option b is 42.0. Wait, maybe I made a mistake. Wait, the equation: \(2C + O_2
ightarrow 2CO\). So 1 mole \(O_2\) gives 2 moles \(CO\). So 1.50 moles \(O_2\) gives \(2\times1.50 = 3.00\) moles \(CO\). Molar mass of \(CO\) is 28 g/mol. So 3 × 28 = 84. But the option a is 84.0 g. But the selected option is b. Wait, maybe the equation was written wrong? Wait, maybe the equation is \(2C + O_2
ightarrow 2CO\), but maybe the user made a typo. Wait, no, let's check again. Wait, 1.50 mol \(O_2\), mole ratio \(O_2:CO = 1:2\), so moles \(CO = 3.00\) mol. Molar mass \(CO = 28\) g/mol. So mass = 3 × 28 = 84 g. So option a is correct? But the selected option is b. Wait, maybe the equation is \(C + O_2
ightarrow CO_2\), no, the question says carbon monoxide. Wait, maybe the equation is \(2C + O_2
ightarrow 2CO\), so 1 mole \(O_2\) gives 2 moles \(CO\). So 1.50 moles \(O_2\) gives 3 moles \(CO\). 3 moles × 28 g/mol = 84 g. So answer is a) 84.0 g. But the original selected option is b. Maybe a mistake in the problem or my calculation. Wait, let's recalculate. Molar mass of CO: C is 12.01, O is 16.00, so 28.01 g/mol. 3 moles × 28.01 = 84.03 g, which is 84.0 g. So the correct answer should be a) 84.0 g. But maybe the equation was \(C + \frac{1}{2}O_2
ightarrow CO\), so mole ratio \(O_2:CO = 1:2\) as well. Wait, no, the given equation is \(2C + O_2
ightarrow 2CO\), so that's correct. So the mass is 84.0 g. So the answer is a) 84.0 g.

Answer:

a) 84.0 g