Question

question 22 (2 points)
state four ions that are isoelectronic to neon
in each blank, write the chemical symbol followed by the charge. the first blank should be the lowest charge (down to -3) and the last blank should be the highest charge (up +4)
if you were writing iron +2, you would write fe+2. if you were writing bismuth -3. you would write bi-3
biank # 1
blank # 2
blank # 3
blank # 4

Explanation:

Step1: Know neon's electron - count

Neon has 10 electrons.

Step2: Find anions

Oxygen gains 2 electrons to form $O^{2 - }$ with 10 electrons. Nitrogen gains 3 electrons to form $N^{3 - }$ with 10 electrons.

Step3: Find cations

Sodium loses 1 electron to form $Na^{+}$ with 10 electrons. Magnesium loses 2 electrons to form $Mg^{2+}$ with 10 electrons.

Answer:

Blank #1: $N^{3 - }$
Blank #2: $O^{2 - }$
Blank #3: $Na^{+}$
Blank #4: $Mg^{2+}$