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Question
question 23 (mandatory) (1 point) write 2^(-3) as a whole number or fraction without an exponent. a) -1/3 b) 8 c) 1/8 d) -1/8
Step1: Apply negative - exponent rule
By the rule $a^{-n}=\frac{1}{a^{n}}$, for $a = 2$ and $n = 3$, we have $2^{-3}=\frac{1}{2^{3}}$.
Step2: Calculate $2^{3}$
$2^{3}=2\times2\times2 = 8$.
Step3: Get the final result
So, $2^{-3}=\frac{1}{8}$.
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C. $\frac{1}{8}$