Question

question 4 of 25 a climber is attached to a vertical rope that has a tension of 1300 n. if the climber has a mass of 68 kg, what is the net force on the climber? a. 634 n down b. 667 n down c. 634 n up d. 667 n up

Explanation:

Step1: Calculate the weight of the climber

The weight formula is $F = mg$, where $m = 68\ kg$ and $g= 9.8\ m/s^{2}$. So $F_{weight}=68\times9.8 = 666.4\ N\approx667\ N$ (down - ward direction).

Step2: Determine the net force

The tension in the rope $F_{tension}=1300\ N$ (up - ward direction). The net force $F_{net}=F_{tension}-F_{weight}$. So $F_{net}=1300 - 667=633\ N\approx634\ N$ (up - ward direction).

Answer:

C. 634 N up