Question

question 8 of 30 what is the balanced equation for the redox reaction between silver and nitric acid (hno3) that forms nitrogen dioxide and silver ions? a. ag + no3 - -> no2 + ag+ + e - b. ag + 2no3 - -> 2no2 + ag+ + o2 c. ag + 2h+ + no3 - -> no2 + ag+ + h2o + 2e - d. ag + 2h+ + no3 - -> no2 + ag+ + h2o

Explanation:

Step1: Analyze oxidation - reduction

Silver (Ag) is oxidized from 0 oxidation state to +1 in $Ag^+$. Nitrogen in $NO_3^-$ is reduced from +5 in $NO_3^-$ to +4 in $NO_2$.

Step2: Write half - reactions

Oxidation half - reaction: $Ag
ightarrow Ag^+ + e^-$
Reduction half - reaction: $NO_3^-+2H^+ + e^-
ightarrow NO_2 + H_2O$

Step3: Combine half - reactions

Combining the two half - reactions gives $Ag + 2H^+ + NO_3^-
ightarrow NO_2+Ag^+ + H_2O$

Answer:

D. $Ag + 2H^+ + NO_3^-
ightarrow NO_2 + Ag^+ + H_2O$