Question

question 6 of 30
what is the molarity of 820 ml of ki solution that contains 36.52 g of ki?
the periodic table
a. 45 mol/l
b. 0.45 mol/l
c. 2.7×10⁻⁴ mol/l
d. 0.27 mol/l

Explanation:

Step1: Calculate molar mass of KI

The molar mass of K (potassium) is approximately 39.10 g/mol and I (iodine) is approximately 126.90 g/mol. So, the molar mass of KI, $M_{KI}=39.10 + 126.90=166.00$ g/mol.

Step2: Calculate moles of KI

Use the formula $n=\frac{m}{M}$, where $m = 36.52$ g and $M = 166.00$ g/mol. So, $n=\frac{36.52}{166.00}=0.22$ mol.

Step3: Convert volume to liters

The volume $V = 820$ mL. Since 1 L = 1000 mL, $V=820\div1000 = 0.82$ L.

Step4: Calculate molarity

Use the formula $M=\frac{n}{V}$, where $n = 0.22$ mol and $V = 0.82$ L. So, $M=\frac{0.22}{0.82}\approx0.27$ mol/L.

Answer:

D. 0.27 mol/L