Question

question 6 of 30
what type of molecule is shown below?

h h h h h h

h—c—c—c—c—c—c—h

h h h h h h

a. an alkene
b. an aromatic
c. an alkyne
d. an alkane

Explanation:

1. Recall the definitions of each type:

• Alkenes have at least one carbon - carbon double bond ($C = C$).
• Aromatics have a benzene - like ring structure (a cyclic, planar, conjugated system with $4n + 2$ $\pi$ electrons).
• Alkynes have at least one carbon - carbon triple bond ($C\equiv C$).
• Alkanes have only single carbon - carbon bonds ($C - C$) and are saturated hydrocarbons (each carbon is bonded to the maximum number of hydrogen atoms).

1. Analyze the given structure: The molecule shown has only single bonds between carbon atoms (all $C - C$ bonds are single) and follows the general formula for alkanes $C_nH_{2n + 2}$ (for $n = 6$, the formula would be $C_6H_{14}$, which matches the number of C and H atoms here: 6 C atoms and 14 H atoms). There are no double bonds, triple bonds, or aromatic ring structures.

Answer:

D. An alkane