Question

question 1 34% of ua students are known to use macbooks. 72% are known to use iphones. assume the probability of intersection is 29%. a student is selected at random and questioned about their technology usage. what is the probability of the student using at least 1 of the two devices? 77% 34% 29% 72%

Explanation:

Step1: Recall the formula for the probability of the union

Let \(A\) be the event of using i - phones (\(P(A)=0.72\)) and \(B\) be the event of using Mac - Books (\(P(B) = 0.34\)), and \(P(A\cap B)=0.29\). The formula for \(P(A\cup B)\) is \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\).

Step2: Substitute the values into the formula

Substitute \(P(A) = 0.72\), \(P(B)=0.34\) and \(P(A\cap B)=0.29\) into the formula: \(P(A\cup B)=0.72 + 0.34-0.29\).

Step3: Calculate the result

\(0.72+0.34 - 0.29=0.77\).

Answer:

77%