Question

question
express in simplest radical form.
\sqrt{49}
answer attempt 1 out of 2

Explanation:

Step1: Recall the square root definition

The square root of a number \( x \), denoted as \( \sqrt{x} \), is a value \( y \) such that \( y^2 = x \). We need to find \( y \) for \( x = 49 \) where \( y^2=49 \).

Step2: Find the number whose square is 49

We know that \( 7\times7 = 49 \), which can be written as \( 7^2=49 \). So, by the definition of square root, \( \sqrt{49}=\sqrt{7^2} \). And for a non - negative real number \( a \), \( \sqrt{a^2}=a \) (when \( a\geq0 \)). Since \( 7\geq0 \), \( \sqrt{7^2} = 7 \).

Answer:

\( 7 \)