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question factor completely. 6x^{2}-11x + 4

Question

question
factor completely.
6x^{2}-11x + 4

Explanation:

Step1: Multiply leading and constant terms

$6\times4 = 24$

Step2: Find two numbers for -11

We need two numbers that multiply to 24 and add up to - 11. The numbers are -8 and -3 since $(-8)\times(-3)=24$ and $-8+( - 3)=-11$.

Step3: Rewrite middle - term

$6x^{2}-8x-3x + 4$

Step4: Group terms

$(6x^{2}-8x)-(3x - 4)$

Step5: Factor out GCF from each group

$2x(3x - 4)-1(3x - 4)$

Step6: Factor out common binomial

$(2x - 1)(3x - 4)$

Answer:

$(2x - 1)(3x - 4)$