Question

question
factor completely.
$6x^2 - 61x + 10$
answer attempt 1 out of 2

Explanation:

Step1: Find two numbers that multiply to \(6\times10 = 60\) and add up to \(-61\). The numbers are \(-60\) and \(-1\).

Rewrite the middle term using these numbers: \(6x^{2}-60x - x + 10\)

Step2: Group the first two and last two terms.

\((6x^{2}-60x)+(-x + 10)\)

Step3: Factor out the greatest common factor from each group.

\(6x(x - 10)-1(x - 10)\)

Step4: Factor out the common binomial factor \((x - 10)\).

\((6x - 1)(x - 10)\)

Answer:

\((6x - 1)(x - 10)\)