Question

question 6 (fill - in - the - blank worth 4 points) (06.03r mc) a large emerald with a mass of 378.24 grams was recently discovered in a mine. if the density of the emerald is 2.76\\(\frac{grams}{cm^{3}}\\), what is the volume? round to the nearest hundredth when necessary, and only enter numerical values, which can include a decimal point. answer for blank 1:

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. We need to solve for $V$, so $V = \frac{m}{
ho}$.

Step2: Substitute given values

Given $m = 378.24$ grams and $
ho=2.76\frac{grams}{cm^{3}}$. Then $V=\frac{378.24}{2.76}$.

Step3: Calculate the volume

$V = 137.0435$ $cm^{3}$. Rounding to the nearest hundredth, we get $V = 137.04$ $cm^{3}$.

Answer:

137.04