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Question
question
find the 12th term of the geometric sequence 5, 15, 45, ...
answer attempt 1 out of 2
Step1: Identify common ratio $r$
$r = \frac{15}{5} = 3$
Step2: Recall geometric term formula
The $n$-th term of a geometric sequence is $a_n = a_1 r^{n-1}$, where $a_1=5$, $n=12$, $r=3$.
Step3: Substitute values into formula
$a_{12} = 5 \times 3^{12-1} = 5 \times 3^{11}$
Step4: Calculate $3^{11}$ and final value
$3^{11}=177147$, so $a_{12}=5 \times 177147 = 885735$
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885735