Question

question
find m∠dcb.
(there is a triangle with vertices b, c, d. sides bc and dc are marked as equal. angle at d is 47°.)
answer attempt 1 out of

Explanation:

Step1: Identify triangle type

The triangle \( \triangle DCB \) has two equal sides (marked with ticks), so it's isosceles with \( \angle B = \angle D \). Given \( \angle D = 47^\circ \), so \( \angle B = 47^\circ \).

Step2: Sum of angles in triangle

The sum of angles in a triangle is \( 180^\circ \). Let \( \angle DCB = x \). Then \( x + 47^\circ + 47^\circ = 180^\circ \).

Step3: Solve for \( x \)

Simplify: \( x + 94^\circ = 180^\circ \). Subtract \( 94^\circ \) from both sides: \( x = 180^\circ - 94^\circ = 86^\circ \).

Answer:

\( 86^\circ \)