Question

question
find the distance between the two points rounding to the nearest tenth (if necessary).
$(3, 2)$ and $(6, 0)$
answer attempt 1 out of 2

Explanation:

Step1: Recall distance formula

The distance $d$ between $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step2: Assign coordinates

Let $(x_1,y_1)=(3,2)$ and $(x_2,y_2)=(6,0)$

Step3: Compute coordinate differences

$x_2-x_1=6-3=3$, $y_2-y_1=0-2=-2$

Step4: Square and sum differences

$(3)^2+(-2)^2=9+4=13$

Step5: Calculate square root

$d=\sqrt{13}\approx3.6055$

Step6: Round to nearest tenth

Round $3.6055$ to 1 decimal place

Answer:

3.6