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Question
question 6
find the translation rule and the scale factor of the dilation transforming the circle, $c_2$ to $c_1$ .
Step1: Find the centers of \( C_1 \) and \( C_2 \)
The center of \( C_2 \) is at \( (0, 3) \) (from the graph, the green dot). The center of \( C_1 \) is at \( (-8, -2) \) (from the graph, the red dot).
Step2: Determine the translation rule
To translate \( C_2 \) to \( C_1 \), we find the change in \( x \)-coordinate and \( y \)-coordinate.
Change in \( x \): \( -8 - 0 = -8 \) (move 8 units left).
Change in \( y \): \( -2 - 3 = -5 \) (move 5 units down).
So the translation rule is \( (x, y) \to (x - 8, y - 5) \).
Step3: Find the radii of \( C_1 \) and \( C_2 \)
Count the grid units for the radius. For \( C_2 \), the radius (from center \( (0,3) \) to the top \( (0,9) \)) is \( 9 - 3 = 6 \). For \( C_1 \), the radius (from center \( (-8, -2) \) to the top, e.g., \( (-8, 1) \)): wait, better to count the diameter. \( C_2 \) spans from \( x = -5 \) to \( x = 5 \) (so diameter 10? Wait, no, let's check the grid. Wait, the green circle \( C_2 \): center at \( (0,3) \), bottom at \( (0, -3) \), so radius is \( 3 - (-3) = 6 \) (vertical distance). The red circle \( C_1 \): center at \( (-8, -2) \), top at \( (-8, 1) \)? Wait, no, the red circle: from \( x = -10 \) to \( x = -6 \) (diameter 4), so radius 2. Wait, \( C_2 \) radius: from \( (0,3) \) to \( (0,9) \) is 6 units (vertical), so radius 6. \( C_1 \): from \( (-8, -2) \) to \( (-8, 1) \) is 3? Wait, no, let's count the grid squares. Each grid square is 1 unit. \( C_2 \): center \( (0,3) \), rightmost point \( (5,3) \), so radius 5? Wait, maybe I made a mistake. Let's look at the graph again. \( C_2 \) (green) has center at \( (0,3) \), and it touches \( x = -5 \) and \( x = 5 \) (so diameter 10, radius 5). \( C_1 \) (red) has center at \( (-8, -2) \), and it touches \( x = -10 \) and \( x = -6 \) (diameter 4, radius 2). Wait, no, \( C_1 \): from \( x = -10 \) to \( x = -6 \), that's 4 units, so radius 2. \( C_2 \): from \( x = -5 \) to \( x = 5 \), that's 10 units, radius 5? Wait, no, the vertical: \( C_2 \) from \( y = -3 \) to \( y = 9 \), that's 12 units, radius 6. Wait, maybe better to calculate the scale factor as \( \frac{\text{radius of } C_1}{\text{radius of } C_2} \). Wait, when transforming \( C_2 \) to \( C_1 \), dilation scale factor is \( \frac{r_1}{r_2} \). Let's find correct radii.
Wait, \( C_2 \): center \( (0,3) \), top at \( (0,9) \), so radius \( 9 - 3 = 6 \). \( C_1 \): center \( (-8, -2) \), top at \( (-8, 1) \), so radius \( 1 - (-2) = 3 \)? No, the red circle: from \( (-8, -2) \) to \( (-8, 1) \) is 3 units? But the red circle looks smaller. Wait, maybe \( C_2 \) radius is 5 (from \( (0,3) \) to \( (5,3) \)), and \( C_1 \) radius is 2 (from \( (-8, -2) \) to \( (-6, -2) \)). Wait, I think I messed up. Let's do it properly.
\( C_2 \) (green): center \( (0,3) \), rightmost point \( (5,3) \), so radius \( 5 - 0 = 5 \). \( C_1 \) (red): center \( (-8, -2) \), rightmost point \( (-6, -2) \), so radius \( -6 - (-8) = 2 \). So scale factor \( k = \frac{\text{radius of } C_1}{\text{radius of } C_2} = \frac{2}{5} \)? Wait, no, wait: when dilating \( C_2 \) to \( C_1 \), the scale factor is \( \frac{r_1}{r_2} \). Wait, \( C_2 \) is the original (pre-image), \( C_1 \) is the image. So scale factor \( k = \frac{\text{image radius}}{\text{pre-image radius}} \).
Wait, let's check the vertical: \( C_2 \) center \( (0,3) \), bottom \( (0, -3) \), so radius 6 (3 - (-3) = 6). \( C_1 \) center \( (-8, -2) \), bottom \( (-8, -5) \), so radius \( -2 - (-5) = 3 \). So scale factor \( \frac{3}{6} = \frac{1}{2} \)? Wait, now I'm confused. Let's count the number of grid sq…
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Translation rule: \( (x, y) \to (x - 8, y - 5) \), Scale factor: \( \frac{1}{2} \) (Note: Depending on radius calculation, but the key steps are finding the center translation and the ratio of radii.)