Question

question 2 how many atoms are in al₂(so₄)₃? (note: corrected from potential typo in original ocr for clarity)

Explanation:

Step1: Identify the formula components

The formula is \( \text{Al}_2(\text{SO}_4)_3 \). Let's break it down:

• For \( \text{Al} \) (Aluminum): The subscript is 2, so number of Al atoms = 2.
• For \( \text{SO}_4 \) (Sulfate ion): The subscript outside the parentheses is 3, and inside the parentheses, we have S (Sulfur) with subscript 1 and O (Oxygen) with subscript 4.

Step2: Calculate S atoms

Number of S atoms: Inside each \( \text{SO}_4 \) there is 1 S, and there are 3 \( \text{SO}_4 \) groups. So \( 1\times3 = 3 \) S atoms.

Step3: Calculate O atoms

Number of O atoms: Inside each \( \text{SO}_4 \) there are 4 O, and there are 3 \( \text{SO}_4 \) groups. So \( 4\times3 = 12 \) O atoms.

Step4: Sum all atoms

Total atoms = Al atoms + S atoms + O atoms = \( 2 + 3 + 12 \)
\( 2+3 = 5 \), then \( 5 + 12 = 17 \)

Answer:

17