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Question
question 5 (mandatory) (1 point) if 3^{2x - 3}=27, then x is equal to a) 2 b) 6 c) 3 d) 4
Step1: Rewrite 27 as a power of 3
Since $27 = 3^3$, the equation $3^{2x - 3}=27$ becomes $3^{2x - 3}=3^3$.
Step2: Set exponents equal
If $a^m=a^n$, then $m = n$. So, $2x-3 = 3$.
Step3: Solve for x
Add 3 to both sides: $2x=3 + 3=6$. Then divide both sides by 2: $x=\frac{6}{2}=3$.
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c) 3