Question

question 2 (1 point)
a 10-kg box sitting on a horizontal surface is pulled by a 5.0-n force. a 3.0-n friction force retards the motion. what is the acceleration of the object?
0.20 m/s2
0.30 m/s2
0.50 m/s2
5.0 m/s2

Explanation:

Step1: Find net force

Net force \( F_{net} = F_{pull} - F_{friction} \)
\( F_{net} = 5.0\,\text{N} - 3.0\,\text{N} = 2.0\,\text{N} \)

Step2: Apply Newton's second law

Newton's second law: \( F = ma \) → \( a = \frac{F_{net}}{m} \)
Mass \( m = 10\,\text{kg} \), so \( a = \frac{2.0\,\text{N}}{10\,\text{kg}} = 0.20\,\text{m/s}^2 \)

Answer:

0.20 m/s² (corresponding to the option: 0.20 m/s2)