Question

question 7 (1 point)
hcl + naoh --> h₂o + nacl
2.87g + ____g 3.75g + 1.98g
what is the mass of the sodium hydroxide?
a 2.86
b 5.73
c 6.62
d 4.85
question 8 (1 point)
hydrogen and oxygen react chemically to form water. how much water would form if 14.8g of hydrogen reacted with 34.8g of oxygen? h₂ + o₂ --> h₂o do not include the units in your answer. ____g
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question 9 (1 point)
when ammonium nitrate nh₄no₃ explodes, the products are nitrogen, oxygen, and water. when 40 grams of ammonium nitrate explodes, 14 grams of nitrogen and 8 grams of oxygen form. how many grams of water form? nh₄no₃ --> n₂ + o₂ + h₂o ____

Explanation:

Question 7

Step1: Apply law of conservation of mass

According to the law of conservation of mass, the total mass of reactants equals the total mass of products. Let the mass of NaOH be $x$. So, $2.87 + x=3.75 + 1.98$.

Step2: Solve for $x$

$x=(3.75 + 1.98)-2.87$.
$x = 2.86$.

Step1: Write balanced chemical equation

The balanced equation for the reaction of hydrogen and oxygen to form water is $2H_2+O_2
ightarrow2H_2O$. First, find the moles of $H_2$ and $O_2$. The molar - mass of $H_2$ is $2g/mol$ and of $O_2$ is $32g/mol$. Moles of $H_2=\frac{14.8}{2}=7.4mol$, moles of $O_2=\frac{34.8}{32}=1.0875mol$.

Step2: Determine limiting reactant

From the balanced equation, the mole - ratio of $H_2$ to $O_2$ is $2:1$. For $1.0875mol$ of $O_2$, the amount of $H_2$ required is $2\times1.0875 = 2.175mol$. Since we have $7.4mol$ of $H_2$, $O_2$ is the limiting reactant.

Step3: Calculate mass of water formed

From the balanced equation, the mole - ratio of $O_2$ to $H_2O$ is $1:2$. Moles of $H_2O$ formed $=2\times1.0875 = 2.175mol$. The molar - mass of $H_2O$ is $18g/mol$. Mass of $H_2O$ formed $=2.175\times18 = 39.15g$.

Step1: Apply law of conservation of mass

Let the mass of water be $x$. According to the law of conservation of mass, the mass of the reactant ($40g$ of $NH_4NO_3$) equals the sum of the masses of the products. So, $40=14 + 8+x$.

Step2: Solve for $x$

$x=40-(14 + 8)$.
$x = 18$.

Answer:

a. 2.86

Question 8