Question

question 6 (problem reference 5 - 1) a 60 kg cyclist turns a corner with a radius of 50 m at a speed of 20 m/s. what is the magnitude of the cyclists centripetal acceleration? 8.0 m/s² 25 m/s² 0.4 m/s² 9.8 m/s²

Explanation:

Step1: Recall centripetal - acceleration formula

The formula for centripetal acceleration is $a_c=\frac{v^{2}}{r}$, where $v$ is the speed and $r$ is the radius of the circular path.

Step2: Substitute given values

We are given that $v = 20\ m/s$ and $r=50\ m$. Substituting these values into the formula: $a_c=\frac{(20)^2}{50}$.

Step3: Calculate the result

First, $(20)^2 = 400$. Then, $\frac{400}{50}=8\ m/s^{2}$.

Answer:

$8.0\ m/s^{2}$