Question

question 2 2 pts cc.2.2.hs.d.10 find the discrimin the number and t x² - 12x + 36 = select 0 288 -24 108 the discriminant is select so there is/ are select

Explanation:

Step1: Recall discriminant formula

For a quadratic equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is given by \(D = b^2 - 4ac\).

Step2: Identify coefficients

In the equation \(x^2 - 12x + 36 = 0\), we have \(a = 1\), \(b = -12\), and \(c = 36\).

Step3: Calculate discriminant

Substitute the values into the formula: \(D = (-12)^2 - 4(1)(36)\)
First, calculate \((-12)^2 = 144\) and \(4(1)(36) = 144\).
Then, \(D = 144 - 144 = 0\).

Answer:

The discriminant is \(0\). So, for the number of solutions, when the discriminant is \(0\), there is \(1\) real solution (a repeated root). But for the discriminant value, the answer is \(0\).