Question

question 1 1 pts indicate if the subshell is possible. 2s choose 3f choose not possible possible 4d choose 2d choose

Explanation:

Step1: Recall quantum - number rules

The principal quantum number \(n\) can take values \(n = 1,2,3,\cdots\). The angular - momentum quantum number \(l\) can take values \(l=0,1,\cdots,n - 1\). The sub - shells are named as \(s(l = 0)\), \(p(l = 1)\), \(d(l = 2)\), \(f(l = 3)\).

Step2: Analyze 2s

For \(n = 2\), \(l\) can be \(0\) or \(1\). When \(l = 0\), it is the \(s\) sub - shell. So, the \(2s\) sub - shell is possible.

Step3: Analyze 3f

For \(n = 3\), \(l\) can take values \(l=0,1,2\). Since \(l\) cannot be \(3\) (for \(f\) sub - shell, \(l = 3\)), the \(3f\) sub - shell is not possible.

Step4: Analyze 4d

For \(n = 4\), \(l\) can take values \(l = 0,1,2,3\). When \(l = 2\), it is the \(d\) sub - shell. So, the \(4d\) sub - shell is possible.

Step5: Analyze 2d

For \(n = 2\), \(l\) can be \(0\) or \(1\). Since \(l\) cannot be \(2\) (for \(d\) sub - shell, \(l = 2\)), the \(2d\) sub - shell is not possible.

Answer:

2s: possible
3f: not possible
4d: possible
2d: not possible