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question solve for x. round to the nearest tenth of a degree, if necess…

Question

question solve for x. round to the nearest tenth of a degree, if necessary.

Explanation:

Step1: Identify the trigonometric ratio

We know that $\sin x=\frac{\text{opposite}}{\text{hypotenuse}}$. In the right - triangle, the side opposite to angle $x$ is 20 and the hypotenuse is 27. So, $\sin x=\frac{20}{27}$.

Step2: Solve for $x$

We use the inverse - sine function. $x = \sin^{-1}(\frac{20}{27})$.
Using a calculator, $x=\sin^{-1}(\frac{20}{27})\approx47.4^{\circ}$.

Answer:

$47.4^{\circ}$